30x^2+19x=63

Solution for 30x^2+19x=63 equation:

30x^2+19x=63

We move all terms to the left:

30x^2+19x-(63)=0

a = 30; b = 19; c = -63;
Δ = b2-4ac
Δ = 192-4·30·(-63)
Δ = 7921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7921}=89$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-89}{2*30}=\frac{-108}{60}
=-1+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+89}{2*30}=\frac{70}{60}
=1+1/6
$